Peter Lindemann video on Tesla cold hole
Posted: Sun Jul 21, 2024 3:20 pm
It appears Tesla fanboys are oblivious to basic science.
Tom recently posted a link to another forum where he continues his endless rant against Carnot and whatever he can get away with. In this post
https://talkrational.org/index.php/topi ... #msg458979
Tom brings up Lindemann video on Tesla "Self Actuating Engine" aka cold hole scheme. You can watch the video via above link or via youtube direct
https://www.youtube.com/watch?v=6lLXvOodPlo
which has plenty of Tesla fanboy comments. Here's some screenshots...
As Tom mentions in talkrational forum, Lindemann's pitch is waaaay more complicated than necessary, but that's the con.
I always thought that Tom's cold hole pipe dream was focused on single engine, but if he wants to raise the bar and go duplex, let's see how this 'new' approach plays out...
I'm going to use a simple 300k 'cold hole' vs typical cryo scheme. Consider 2 similar Otto cycle machines where A is reefer and B is engine. Both have 300-1200k diatomic (air) cycles with 6:1 volume ratios. Within these values, the temperature ratio will vary by 2 during both compression and expansion. Therefore, reefer A will adiabatically compress 600-1200k, then isochorically cool 1200-600k, then adiabatically expand 600-300k, then isochorically heat 300-600k and engine B will isochorically heat 600-1200k, then adiabatically expand 1200-600k, then isochorically cool 600-300k, then adiabatically compress 300-600k. Thus, the sink reefer A = source engine B, and sink engine B = source reefer A.
Lindemann throws in enough BS to appear convincing like that Wpos from reefer A is .85 Wneg, but he avoids details. In my example here, the eff both Otto cycles is .50 simply because it's locked by the volume ratio. Furthermore, I picked an example where each process is equal work vs heat...in vs out. However, the thermal ratio can vary, and this would alter the Wpos/Wneg ratio (aka backwork ratio) but the thermal efficiency would remain constant, here .50 due to 6:1 volume ratio. Therefore, Lindemann's claim that reefer A Wpos = .85 Wneg could be correct with different values, but he's only pitching it this way to show reefer A is only running .15 energy deficit which is easier to 'compensate' for with engine B output.
My favorite part of Lindemann's con is his flow chart with ambient input shown as a Joe 6-pack car radiator of massive proportions to con you into thinking his scheme runs on massive amount of ambient heat energy, despite any heat to reefer A cycle has already been supplied by engine B sink. He achieves this illusion via his flowchart having reefer cycle running clockwise vs typical PV would have reefer cycle running counter-clockwise.
Another gimmick he throws in is engine B being a Stirling which is good buzz, but has another hidden head game where the partially learned think great...300-1200k Stirling =. 75 eff vs Otto = .50 therefore, system gains .50 if everything is 100% efficient. Ha...the 1200-600k temperature gradient from reefer A sink will gain no advantage over 600k engine B source when B is Stirling. His con is making some idiot/s think 1200k Tmax reefer A sink is T constant engine B source.
You can move the proportions of this sample cycle up and down the thermal scale and nothing changes. It's just like how altering the buffer pressure doesn't change the work area. I simply chose an ambient 'cold hole' to nix the voodoo.
Tom recently posted a link to another forum where he continues his endless rant against Carnot and whatever he can get away with. In this post
https://talkrational.org/index.php/topi ... #msg458979
Tom brings up Lindemann video on Tesla "Self Actuating Engine" aka cold hole scheme. You can watch the video via above link or via youtube direct
https://www.youtube.com/watch?v=6lLXvOodPlo
which has plenty of Tesla fanboy comments. Here's some screenshots...
As Tom mentions in talkrational forum, Lindemann's pitch is waaaay more complicated than necessary, but that's the con.
I always thought that Tom's cold hole pipe dream was focused on single engine, but if he wants to raise the bar and go duplex, let's see how this 'new' approach plays out...
I'm going to use a simple 300k 'cold hole' vs typical cryo scheme. Consider 2 similar Otto cycle machines where A is reefer and B is engine. Both have 300-1200k diatomic (air) cycles with 6:1 volume ratios. Within these values, the temperature ratio will vary by 2 during both compression and expansion. Therefore, reefer A will adiabatically compress 600-1200k, then isochorically cool 1200-600k, then adiabatically expand 600-300k, then isochorically heat 300-600k and engine B will isochorically heat 600-1200k, then adiabatically expand 1200-600k, then isochorically cool 600-300k, then adiabatically compress 300-600k. Thus, the sink reefer A = source engine B, and sink engine B = source reefer A.
Lindemann throws in enough BS to appear convincing like that Wpos from reefer A is .85 Wneg, but he avoids details. In my example here, the eff both Otto cycles is .50 simply because it's locked by the volume ratio. Furthermore, I picked an example where each process is equal work vs heat...in vs out. However, the thermal ratio can vary, and this would alter the Wpos/Wneg ratio (aka backwork ratio) but the thermal efficiency would remain constant, here .50 due to 6:1 volume ratio. Therefore, Lindemann's claim that reefer A Wpos = .85 Wneg could be correct with different values, but he's only pitching it this way to show reefer A is only running .15 energy deficit which is easier to 'compensate' for with engine B output.
My favorite part of Lindemann's con is his flow chart with ambient input shown as a Joe 6-pack car radiator of massive proportions to con you into thinking his scheme runs on massive amount of ambient heat energy, despite any heat to reefer A cycle has already been supplied by engine B sink. He achieves this illusion via his flowchart having reefer cycle running clockwise vs typical PV would have reefer cycle running counter-clockwise.
Another gimmick he throws in is engine B being a Stirling which is good buzz, but has another hidden head game where the partially learned think great...300-1200k Stirling =. 75 eff vs Otto = .50 therefore, system gains .50 if everything is 100% efficient. Ha...the 1200-600k temperature gradient from reefer A sink will gain no advantage over 600k engine B source when B is Stirling. His con is making some idiot/s think 1200k Tmax reefer A sink is T constant engine B source.
You can move the proportions of this sample cycle up and down the thermal scale and nothing changes. It's just like how altering the buffer pressure doesn't change the work area. I simply chose an ambient 'cold hole' to nix the voodoo.