Calculating volume ratios using PV=nRT
Posted: Thu Sep 14, 2023 5:10 pm
Here's the click bait version...Given ideal conditions(and I'll explain below why they are achievable) in a 300k to 600k Gamma cycle, compression and expansion work does not even start until the displacer swept volume is smaller than power piston swept volume. In other words, less than 1:1.
For this I am going to assume my theory in this thread is true. viewtopic.php?f=1&t=5561 Furthermore, I'm going to assume some other "ideals". That is mainly having enough heat sink capacity to reach near isothermal values as the power piston moves from high volume to low volume. The other ideal is that the gas inside the engine is reaching a high of 600 and a low of 300. This is definitely doable, even if the hot end needs to be a good bit higher to reach a true 300k delta.
We will be using PV=nRT to illustrate this given a known delta T, displacer and power piston displacement.
Displacer = 100cc
Power piston= 100cc
Lets start by calculating the moles of gas in our engine at 450k and power piston at MDC, or 150cc total volume. We get .004 mol.
Now when we figure the volume of .004 mol at 300k we get 100cc
So then at 600k we of course get 200cc.
What this suggests is that given our (not so far-fetched at low rpm) ideal constraints at a 1:1 swept volume ratio, an engine at operating temperature actually loses zero work to compression and expansion of the gas. So to gain efficiency, we must reduce the volume of the displacer even further.
What's really interesting to me, is that an LTD with a 60:1 volume ratio running on about a 10F delta is actually at about this zero point of compression and expansion.
Now, I'm sure there is a bunch of high level math that I am leaving out, but why not construct such an engine and do some testing on it? For my little LTD in this thread viewtopic.php?f=1&t=5570 , I've determined that for a delta of Tmin=50F and Tmax=250F, I need roughly 15cc of power piston displacement to get to this "zero point".
I am using chat GPT to help me work out a formula to quickly find this zero point, given basic temperature and displacement constraints.
For this I am going to assume my theory in this thread is true. viewtopic.php?f=1&t=5561 Furthermore, I'm going to assume some other "ideals". That is mainly having enough heat sink capacity to reach near isothermal values as the power piston moves from high volume to low volume. The other ideal is that the gas inside the engine is reaching a high of 600 and a low of 300. This is definitely doable, even if the hot end needs to be a good bit higher to reach a true 300k delta.
We will be using PV=nRT to illustrate this given a known delta T, displacer and power piston displacement.
Displacer = 100cc
Power piston= 100cc
Lets start by calculating the moles of gas in our engine at 450k and power piston at MDC, or 150cc total volume. We get .004 mol.
Now when we figure the volume of .004 mol at 300k we get 100cc
So then at 600k we of course get 200cc.
What this suggests is that given our (not so far-fetched at low rpm) ideal constraints at a 1:1 swept volume ratio, an engine at operating temperature actually loses zero work to compression and expansion of the gas. So to gain efficiency, we must reduce the volume of the displacer even further.
What's really interesting to me, is that an LTD with a 60:1 volume ratio running on about a 10F delta is actually at about this zero point of compression and expansion.
Now, I'm sure there is a bunch of high level math that I am leaving out, but why not construct such an engine and do some testing on it? For my little LTD in this thread viewtopic.php?f=1&t=5570 , I've determined that for a delta of Tmin=50F and Tmax=250F, I need roughly 15cc of power piston displacement to get to this "zero point".
I am using chat GPT to help me work out a formula to quickly find this zero point, given basic temperature and displacement constraints.