LTD temperature using PV = nRT
Posted: Mon May 22, 2023 2:03 am
Using this online calculator:
https://www.calculatorsoup.com/calculat ... as-law.php
I first calculated the number of moles in 44.35 cm3 at atmospheric pressure (101.325 kPa) using an engine inside working fluid temperature of 190°F (hot cup of water)
The results being 0.014975 moles (rounded)
And 44.35 cm3 at an ambient temperature of 70°F
Result 0.0018367 (rounded)
Assuming the number of moles inside the engine remains static I then used the actual PV readings of an LTD from this diagram.
After spending most of the day plotting temperatures and connecting the dots, I ended up with these "isotherms" superimposed over the PV diagram.
There is approximately a 10° ∆T between Tmin and T max
Rather surprisingly to me the lowest temperature reached by the working fluid appears to be in the return "compression" stroke while the working fluid is still just very slightly below atmospheric pressure (horizontal line)
The temperature appears to drop just 1/10th of one degree below the presumed source heat input temperature (189.98°F)
After the pressure increases above atmospheric pressure, the temperature increases about 1.5° at TDC (full compression, minimum volume 191.56°F)
From TDC pressure and temperature rise the pressure peaking at about 102.1 kPa the temperature risen to about 195°F
From there the temperature continues to rise, peaking at about 200°F. The pressure simultaneously dropping.
Needless to say, I don't see how these values could be correct as the temperature, according to the ideal gas law has risen about 10° above the hot input temperature from a starting point of 190° up to nearly 200° then begins to drop in temperature prior to BDC.
The Ideal gas law, however does not take into account cooling by expansion and/or work output.
Logically, according to the ideal gas law, the more heat a gas takes in the more it expands. So reciprocally, the more it has expanded the hotter it must be, however, it is not logical that the gas in a Stirling engine could heat up, above the source temperature while expanding
Another puzzle is that from BDC as presumably, atmospheric pressure is driving the piston inward, although the working fluid temperature is falling, it stays well above ambient, and also above the heat source temperature almost all the way back until the pressure approaches atmospheric pressure
This seems to make more sense if we assume a source temperature above 200°F. (Say, Boiling water)
My selected starting point and temperature of 190°F at atmospheric pressure lower left where the horizontal 1atm line is crossed were arbitrary.
If a higher source temperature is assumed, then the temperature changes are more or less what would be expected given a 90° displacer advance.
Then at the upper right (hottest temperature) is where the displacer shifts over to expose the sink so temperature and pressure drop.
At the lower left (coldest temperature) is about where the displacer would move back exposing the heat source.
So then how does atmospheric pressure drive the piston inward after BDC if the temperature of the working fluid is still much higher than ambient?
I would suppose, though atmospheric temperature is lower there are more molecules more densely packed.
The working fluid has been heated and expanded and so much of the air has leaked out past the piston, so that the working fluid is "thin" with fewer molecules/cm3
The "weight" of the atmosphere therefore exerts more force on the piston from the outside than the rather thin feeble hot gas inside the engine.
https://www.calculatorsoup.com/calculat ... as-law.php
I first calculated the number of moles in 44.35 cm3 at atmospheric pressure (101.325 kPa) using an engine inside working fluid temperature of 190°F (hot cup of water)
The results being 0.014975 moles (rounded)
And 44.35 cm3 at an ambient temperature of 70°F
Result 0.0018367 (rounded)
Assuming the number of moles inside the engine remains static I then used the actual PV readings of an LTD from this diagram.
After spending most of the day plotting temperatures and connecting the dots, I ended up with these "isotherms" superimposed over the PV diagram.
There is approximately a 10° ∆T between Tmin and T max
Rather surprisingly to me the lowest temperature reached by the working fluid appears to be in the return "compression" stroke while the working fluid is still just very slightly below atmospheric pressure (horizontal line)
The temperature appears to drop just 1/10th of one degree below the presumed source heat input temperature (189.98°F)
After the pressure increases above atmospheric pressure, the temperature increases about 1.5° at TDC (full compression, minimum volume 191.56°F)
From TDC pressure and temperature rise the pressure peaking at about 102.1 kPa the temperature risen to about 195°F
From there the temperature continues to rise, peaking at about 200°F. The pressure simultaneously dropping.
Needless to say, I don't see how these values could be correct as the temperature, according to the ideal gas law has risen about 10° above the hot input temperature from a starting point of 190° up to nearly 200° then begins to drop in temperature prior to BDC.
The Ideal gas law, however does not take into account cooling by expansion and/or work output.
Logically, according to the ideal gas law, the more heat a gas takes in the more it expands. So reciprocally, the more it has expanded the hotter it must be, however, it is not logical that the gas in a Stirling engine could heat up, above the source temperature while expanding
Another puzzle is that from BDC as presumably, atmospheric pressure is driving the piston inward, although the working fluid temperature is falling, it stays well above ambient, and also above the heat source temperature almost all the way back until the pressure approaches atmospheric pressure
This seems to make more sense if we assume a source temperature above 200°F. (Say, Boiling water)
My selected starting point and temperature of 190°F at atmospheric pressure lower left where the horizontal 1atm line is crossed were arbitrary.
If a higher source temperature is assumed, then the temperature changes are more or less what would be expected given a 90° displacer advance.
Then at the upper right (hottest temperature) is where the displacer shifts over to expose the sink so temperature and pressure drop.
At the lower left (coldest temperature) is about where the displacer would move back exposing the heat source.
So then how does atmospheric pressure drive the piston inward after BDC if the temperature of the working fluid is still much higher than ambient?
I would suppose, though atmospheric temperature is lower there are more molecules more densely packed.
The working fluid has been heated and expanded and so much of the air has leaked out past the piston, so that the working fluid is "thin" with fewer molecules/cm3
The "weight" of the atmosphere therefore exerts more force on the piston from the outside than the rather thin feeble hot gas inside the engine.