Re: The TRUTH? η = 1 – (Qc / Qh) = 1 – (Tc / Th)
Posted: Tue Jun 04, 2024 11:17 am
The formulas/equations for calculating work and heat flow assume any contribution from the atmosphere to be zero for a cycle. Therefore the full cycle can be calculated from an absolute pressure and temperature sense, ignoring outside pressure. If outside pressure isn't ignored, the forward and return equations must both be modified.
To explain it simpler. Work out of a single forward stroke is calculated by the absolute inside pressure. And the return stroke the same. If you want to add the outside pressure, you must subtract 14.7 x Area of piston x Volume of stroke from the absolute work done by the inside pressure x the same Area x Volume change.
Note: Inside pressure isn't constant, so it is incorrect to subtract a set inside pressure. Outside pressure is constant, so it is acceptable to use a single value for outside pressure.
The forward work, calculated this way for previous examples, will be much less than 100 J.
It is wrong to add an outside pressure/force to one side of the equation as you've done repeatedly.
Forward stroke:
Wf = Inside Forward Work - Outside Work
Return stroke:
Wr = Outside Work - Inside Return Work
Sum the two:
Work Total = Wt = Wf + Wr = (Inside Forward Work - Outside Work) + (Outside Work - Inside Return Work)
Rearranging:
Wt = Inside Forward Work + Outside Work - Outside Work - Inside Return Work
Canceling the Outside Work:
Work Total = Inside Forward Work - Inside Return Work
This equation shows that you will need a smaller Return Work to get any Net Work output. Back work must be smaller than forward work to get work output. That is accomplished by rejecting heat before and or during the return stroke.
In other words, adding something that cancels with itself, like outside pressure, adds nothing. The beauty of cancelation in an equation, allows the equation to be simplified to the point were assumptions become reality. It was a good assumption to ignore the outside pressure. It canceled anyway.
Hence, n = (Qh-Qc)Qh = (Th-Tc)/Th
It is only true for a complete cycle, because of cancellations in the cycle and ratio. The process must be a complete cycle. It will not work for descriptions of a single stroke.
It is possible to have a return stroke without rejecting heat, it just uses more work, the same amount as Forward work. It is called adiabatic bounce, the same as for a metal spring. The processes stay on a single adiabatic line, forward and return strokes, adiabatic.
Observed conservation of energy, the data used to develop the first law, suggests that any energy put into cooling will be the maximum energy that can be gotten back out. Zero improvement, most likely a detriment, if cooling is added.
The first law leads to the second law by considering a full cycle and quantification of the process. And it proves that there are no Calorics, and some thermal energy becomes work, so not all the energy is loss to the sink. Without Carnot, entropy, the second law and the Carnot theorem, we would still be arguing conservation of calorics. The first and second laws have proven the non-existence of calorics.
To explain it simpler. Work out of a single forward stroke is calculated by the absolute inside pressure. And the return stroke the same. If you want to add the outside pressure, you must subtract 14.7 x Area of piston x Volume of stroke from the absolute work done by the inside pressure x the same Area x Volume change.
Note: Inside pressure isn't constant, so it is incorrect to subtract a set inside pressure. Outside pressure is constant, so it is acceptable to use a single value for outside pressure.
The forward work, calculated this way for previous examples, will be much less than 100 J.
It is wrong to add an outside pressure/force to one side of the equation as you've done repeatedly.
Forward stroke:
Wf = Inside Forward Work - Outside Work
Return stroke:
Wr = Outside Work - Inside Return Work
Sum the two:
Work Total = Wt = Wf + Wr = (Inside Forward Work - Outside Work) + (Outside Work - Inside Return Work)
Rearranging:
Wt = Inside Forward Work + Outside Work - Outside Work - Inside Return Work
Canceling the Outside Work:
Work Total = Inside Forward Work - Inside Return Work
This equation shows that you will need a smaller Return Work to get any Net Work output. Back work must be smaller than forward work to get work output. That is accomplished by rejecting heat before and or during the return stroke.
In other words, adding something that cancels with itself, like outside pressure, adds nothing. The beauty of cancelation in an equation, allows the equation to be simplified to the point were assumptions become reality. It was a good assumption to ignore the outside pressure. It canceled anyway.
Hence, n = (Qh-Qc)Qh = (Th-Tc)/Th
It is only true for a complete cycle, because of cancellations in the cycle and ratio. The process must be a complete cycle. It will not work for descriptions of a single stroke.
It is possible to have a return stroke without rejecting heat, it just uses more work, the same amount as Forward work. It is called adiabatic bounce, the same as for a metal spring. The processes stay on a single adiabatic line, forward and return strokes, adiabatic.
Observed conservation of energy, the data used to develop the first law, suggests that any energy put into cooling will be the maximum energy that can be gotten back out. Zero improvement, most likely a detriment, if cooling is added.
The first law leads to the second law by considering a full cycle and quantification of the process. And it proves that there are no Calorics, and some thermal energy becomes work, so not all the energy is loss to the sink. Without Carnot, entropy, the second law and the Carnot theorem, we would still be arguing conservation of calorics. The first and second laws have proven the non-existence of calorics.