Re: The TRUTH? η = 1 – (Qc / Qh) = 1 – (Tc / Th)
Posted: Sun Apr 21, 2024 12:11 am
All types and size Stirling Engines
https://stirlingengineforum.boydhouse.com/
https://stirlingengineforum.boydhouse.com/viewtopic.php?t=5601
I've been trying to work out what you might mean by this statement.
We have previously determined that buffer pressure has no effect on efficiency, and that charge pressure has little to no effect. So what parameters would have to be changed to reach "super-carnot" (thanks Matt) efficiency?Vincent, I don't know what you want or are striving for, but to get 50% efficiency out of any heat engine would be a very good feather in someone's cap.
Carnot efficiency of 50% with DQh of 100 could be done between 100 K and 200 K. However, a real engine at those temperatures probably wouldn't get much better than about 25%, and it would have to be run on a much colder planet.
It could also run at 300 K and 600 K, for the same efficiencies, but a larger DQh.
If run at 300 K and 1200 K the Carnot Efficiency would be 75% and a real engine might be 37.5%.
0k is only an advantage when a heat engine needs a heat sink which is what Tom is trying to circumvent. However, if you can recycle would be sink heat to source then you don't need a heat sink. Think of this kinda like cooling a steam engine condenser with alcohol that feeds boiler source whereby sink heat returns to source vs ambient.VincentG wrote: ↑Sun Apr 21, 2024 6:10 pm
We have previously determined that buffer pressure has no effect on efficiency, and that charge pressure has little to no effect. So what parameters would have to be changed to reach "super-carnot" (thanks Matt) efficiency?
IOW, does the atmosphere have to be absolute zero? So in that case any atmospheric pressure will do, so long as the temp is 0k?
So if an artificial atmosphere of 0k was maintained, the efficiency of the (ideal)engine itself would be 100%?
Is that the only hold up?
Not to be overly picayune, but I guess I'm overly sensitive about mischaracterizations.matt brown wrote: ↑Sun Apr 21, 2024 8:23 pm ...
0k is only an advantage when a heat engine needs a heat sink which is what Tom is trying to circumvent. ....
The underlined sentence is, I think, clearly an assumption rooted in the Carnot efficiency limit notion, idea, concept, theory, so-called "LAW".Fool wrote: ↑Thu Apr 18, 2024 7:48 pmHopefully that is a little easier to follow. Whomever said this was easy, or simple, has my complete disagreement. LOL....
... So Qhz should have the same relation ship to Qcz that DQh has to DQc, in other words, 'n' is the same. Basically this says that Qcz can be calculated from 'n' and Qhz,
or:
Qcz = Qhz•(1-n)
Substituting that equivalence for Qcz into the 'DQh' equation:
DQh = Qhz - Qcz (DQh equation)
Qcz = Qhz•(1-n)
Substituting and distributing:
DQh = Qhz - Qhz(1-n)
DQh = Qhz - Qhz + n•Qhz
Subtracting:
DQh = n•Qhz (#2)
Combining #1 and #2
n = n•(Qhz - Qcz) / DQh (#1)
DQh = n•Qhz (#2)
#2 into #1:
n = n•(Qhz - Qcz) / n•Qhz
The n's on the right side, of the equals sign, cancel becoming one, and rewriting:
n = (Qhz - Qcz) / Qhz (#3)
Equation #3 shows that DQh and DQc have now become Qhz and Qcz. In retrospect, it seems logical that the efficiency profile should be the same regardless of absolute scale. Substituting in Qhz and Qcz straight across for DQh and DQc makes sense, and would have been faster. That was the mathematical derivation/proof. Note also, that it tends to maximize efficiency by equating DQc with Zero. DQc is not zero, it is just the amount of inevitable heat rejection and with maximum work out.
Now using the equations above for Qhz and Qcz:
Qhz = M•Cv•Th (The equations above)
Qcz = M•Cv•Tc (The equations above)
Substituting the above two lines into equation #3:
n = (Qhz - Qcz) / Qhz (#3)
Here:
n = (M•Cv•Th - M•Cv•Tc) / (M•Cv•Th)
Rearranging and removing the distributed 'M•Cv':
n=M•Cv•(Th-Tc) / (M•Cv•Th)
Canceling 'M•Cv' top and bottom because they become one:
n=(Th-Tc)/Th <<<The final solution.
That shows the logical step by step progression for the mathematical derivation or proof.
Basically we took relative scale Delta heat:
n=(DQh-DQc)/DQh
Converted it to absolute temperature scale heat:
n=(Qhz-Qcz)/Qhz
Then converted it to temperature calculated heat:
n=(Th-Tc)/Th
They are all the same value of n, because they are all the same heat-in heat-out ratios. They are just three different ways of obtaining the same thing.
It's logical to think that higher temperature differences produce higher pressure differences, that make greater power to weight and size ratios, ease of construction, operation, and efficiency increases.
1/10 degree temperature, would be like trying to move a piston with 1/10 of a psi. How can that possibly be as efficient as trying to move a smaller piston with 100 psi.
It would take a piston 1000 times larger in area to develop the same force. Power and efficiency sucking bad bulk would be the down fall. I hope this makes sense in regard to the Carnot Theorem.
And it still probably has little errors. I'm hoping the little errors we've found are it. I don't think they spoil the overall proof, but a proof isn't a proof until all the errors are eliminated. Your help has been much appreciated.
There is no such thing as "Super Carnot Efficiency". The Carnot engine is an example of a perfect engine. Run one backwards as a heat pump and you will return 100% of the heat to the hot plate, ideally. Anyone telling you differently is mistaken. If they have a working device, it will need to proven by independent testing in a reputable laboratory.VincentG wrote: ↑Sun Apr 21, 2024 6:10 pm We have previously determined that buffer pressure has no effect on efficiency, and that charge pressure has little to no effect. So what parameters would have to be changed to reach "super-carnot" (thanks Matt) efficiency?
IOW, does the atmosphere have to be absolute zero? So in that case any atmospheric pressure will do, so long as the temp is 0k?
So if an artificial atmosphere of 0k was maintained, the efficiency of the (ideal)engine itself would be 100%?
Is that the only hold up?
The ratio is the same.Tom Booth wrote:I've been trying to work out what you might mean by this statement.
"Qhz should have the same relation ship to Qcz that DQh has to DQc"
First of all, why "should have"? Is there some question about this?
Let's not bring time travel into this. It is fairly straightforward to use the equivalent of heat and work. How are they get stored is more complicated, and how the conversion proportions are calculated is abstract, but not too bad. Maybe the following link will help :Tom Booth wrote:I doubt you can actually back up that statement. Or what you mean, or are trying to imply I don't know.
Do you suppose that if there is a compression stroke after an isothermal expansion 90% of the joules go back in time so instead of being transformed into work they can go to the "cold reservoir"?
The word "Draw" has the synonym "pull".Tom Booth wrote:I don't think "pulling" is often included in a definition of "contract".
Some definitions from some online dictionaries:
"to cause to draw more closely together"
"to reduce to smaller size by or as if by squeezing or forcing together."
Gases have attractive forces and when cooled or brought closer together by being compressed, the attractive forces get stronger and this can moderate or ebate the pressure.
What way? I don't think I said anything about how magnets work.
Only because you set it up that way so your equations adhere to the Carnot limit theory, from what I can see so far. I'm not all the way through though, so I'll reserve judgement and take another look, however it appears the supposition "should have the same relationship" leads to your arranging the mathematical "proof" accordingly.The ratio is the same.Tom Booth wrote:I've been trying to work out what you might mean by this statement.
"Qhz should have the same relation ship to Qcz that DQh has to DQc"
First of all, why "should have"? Is there some question about this?
Qcz/Qhz = DQc/DQh = 300/400 = 75/100
Should, could, is, will be, has to be, needs to be, is set by mathematical precision, by definition. All just semantics. Look at the equations....
Didn't think so, however I'll continue looking it over.Probably not. ...Tom Booth wrote:Do we ever break out of this self referential loop further down?
Round and round we go.