Here is the graphical solution for all cubes in the range side = 1 to 10 (any dimension you like, cm or kilometres or inches) showing the value (as a curve) of SA:V = 6(s2)/s3.
(You can ignore the curve for spheres which is 4pir2/(4/3)*pir3 - but it too follows a similar shape to cubes and most other simple 3D shapes)
Sorry - not sure why that image came up twice!!
But you can see that the smaller the cube (or sphere) the larger the ratio of surface area to volume becomes.
Back to the main point at issue here.
The ratio of surface area of the working fluid (ie the contact area between engine surfaces and working fluid) to volume of the working fluid is larger in a small engine than it is in a larger engine of the same design. The significance of that is a smaller engine running in steady state conditions will lose MORE heat (to the ambient environment) relative to its mass of working fluid than a larger one will relative to its own mass of working fluid.
Because most measures of Stirling engine efficiency take into account thermal "leakage" from the engine overall, it will always be true to say that this particular effect means that - in this one particular aspect - smaller engines will be intrinsically and unavoidably less efficient than larger engines of the same design.
BUT.... how much less efficient? We haven't discussed that yet, and I'm guessing there isn't a lot of appetite to do that!
It is an interesting way of looking at the problem of developing higher efficiency Stirling cycle engines, though, because you can apply similar (at least related) logic to the different phases (expansion/contraction/work etc) of the cycle as a whole and determine where the losses are likely to be significant and where they might not be so bad.
But maybe this isn't the time or the place.........?